rm_eo 在 Linux、UNIX下居然不同，不解
涩兔子
posted @ 2009年9月02日 16:51
in 未分类
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man regex中有Byte Offsets这样的一段，介绍遍历满足正则表达式条件的所有子串的rm_so（起始位置）和rm_eo（终止位置）;
用到了regmatch_t结构：
typedef struct {
regoff_t rm_so;
regoff_t rm_eo;
} regmatch_t;
有这样的字符串"xzhai=\"Unix/Linux geek\";legendren=\"GOD\";"
想寻找="xxx";里的xxx内容；
while (!regexec(&m_reg, tmp, 1, &m_match, 0))
{
// FIXME: Unix regex`s rm_eo is often 0 test under Mac OS X Leopard;
// But Linux POSIX regex`s rm_eo is normal test under Gentoo Linux
printf("%d - %d\n", m_match.rm_so, m_match.rm_eo);
tmp += m_match.rm_eo;
}
Linux下rm_eo的值是正确的，而UNIX下rm_eo始终为0，不解
- 无匹配
2009年9月05日 16:18
其实不奇怪的阿,linux下有些函数的实现是和unix不一样的. mac os x的实现可能更接近于FreeBSD一些吧.
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